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0.037-3.2x+3.397x^2=0
a = 3.397; b = -3.2; c = +0.037;
Δ = b2-4ac
Δ = -3.22-4·3.397·0.037
Δ = 9.737244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.2)-\sqrt{9.737244}}{2*3.397}=\frac{3.2-\sqrt{9.737244}}{6.794} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.2)+\sqrt{9.737244}}{2*3.397}=\frac{3.2+\sqrt{9.737244}}{6.794} $
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